22.  The capacity of a band-limited additive white Gaussian noise (AWGN) channel is given by \(C=Wlog_2(1+{P\over \sigma^2w})\) bits per second (bps), where W is the channel bandwidth, P is the  average power received and σ2 is the one-sided power spectral density of the AWGN.  For a fixed \({P\over\sigma^2}=1000\) , the channel capacity (in kbps) with infinite bandwidth ( W →∞ ) is  approximately  

(A) 1.44 

(B) 1.08 

(C) 0.72 

(D) 0.36


Answer-(A) 1.44 
Discuss the solution.

Did not found what you are looking for, Ask your doubt or Help by your contribution

Enter your search keyword:

Search form


Here is a chance to join biggest community of technical Students,
Tutors with FREE learning resources and so much more.
It takes less then 60 seconds.