30. The steady state output of the circuit shown in the figure is given by

\(y(t)=A(\omega) \sin(\omega t+\phi(\omega))\). If the amplitude\(|A(\omega)|=0.25\) then the frequency  ω is

(A) \(1\over \sqrt3RC\)

(B) \(2\over \sqrt3RC\)

(C) \(1\over RC\)

(D) \(2\over RC\)


Answer-(B) \(2\over \sqrt3RC\)
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