# 30. The steady state output of the circuit sho...

30. The steady state output of the circuit shown in the figure is given by

$y(t)=A(\omega) \sin(\omega t+\phi(\omega))$. If the amplitude$|A(\omega)|=0.25$ then the frequency  ω is

(A) $1\over \sqrt3RC$

(B) $2\over \sqrt3RC$

(C) $1\over RC$

(D) $2\over RC$

Hint: