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2 level cache

avg access time

1Comment
Arul @innovwelt
23 Mar 2015 11:25 pm

I get the below answer.

Cache A:

avg access time, tA = (0.92 x 4) + 0.08 x (4+100) = 12 ns

Cache B:

avg access time, tB = (0.7 x 2) + 0.3 x (2 + (0.85 x 8) + (0.15 x 108)) = 8.9 ns

tA + tB = 20.9 ns