looks like a)

Only if the program is modified like the following, the answer will be (a)

#include<stdio.h>
#define PRINT(format,x) printf(#x " = %" #format "\n", x)
int integer = 5;
char character = '5';
char *string = "5";
int main()
{
	PRINT(d,string);
	PRINT(d,character);
	PRINT(d,integer);
}

Otherwise, the macro written within printf quotes will not take the proper values of x and format, so will lead to answer (d) None of these.

yes. you are right.

thanks!

When u declare string as a character pointer,it'll hold the base address of the character string,so when u print it with %d as format specifier,it's base address will be printed as an integer

When %d is passed as a format specifier and if we use it to print a character,it's ascii value will be printed and so as the ascii value of '5' is 53,so 53 is printed

and when integer is printed it will output the integer value

Macros can be defined using #define and u can also specify functions as a part of macro.