Inverted paging Example

Ques: Consider a system which has logical address 34 bits and physical address  29 bits  and page size 16kB and memory is byte addressable.Page entry size 8B  then calculate:

  1. Conventional Page table size
  2. Inverted Page table size

 

Answer

Solution:

conventional(normal)Page table size=Number of Pages*page table entry size

=(2^{34}/2^{14})*8B

8MB

Inverted page table size=Number of Frames *Page table entry size

=(2^{29}/2^{14})*8B

256KB

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