Consider bandwidth of line is 100 Mbps and sequence

Consider bandwidth of line is 100 Mbps and sequence number of field consists 32 bits on a TCP machine. How much time it will take to cover all possible sequence numbers? ________________ sec (integer value only).

Answer

Correct answer: 328 sec
Explanation will be posted soon.

5Comments
Sougatamoy Biswas @sougatamoy
4 Feb 2016 07:16 pm

100MB -> 1 sec

100*(2^20) bits -> 1 sec

(2^32)*8 bits-> (2^32)*8/100*(2^20)=327.68 sec=328 sec

Ritwik @ritwikmishra
3 Nov 2016 03:12 pm

sequence no is not a number given to every bit,

it is given every frame, without frame length (or size) this is an incomplete question

priyanka gautam @priyankagautam
22 Nov 2016 05:15 pm

why you have further multiply with 8 ?? 

 

Saif Ahmed @saifahmed
11 Jan 2017 02:35 pm

we take 10 Mbps as 10*(10^6) bits when we talk ablut bandwidth   when we take data size as 10 Mb then we take 10*(2^20)

Ashwani Kumar @ash96kumar
19 Jan 2017 10:59 pm

Answer should br 343

1 sec -----> (100*10^6)/8 seq no.

1 seq no --------> 8/(100*10^6) sec

For 32 bit -------> (2^32 * 8)/(100*10^6) = 343