A FAT (file allocation table) based file syste...

A FAT (file allocation table) based file system is being used and the total overhead of each entry in the FAT is 4 bytes in size. Given a 100×10^6 bytes disk on which the file system is stored and data block size is 10^3 bytes, the maximum size of a file that can be stored on this disk in units of 10^6 bytes is _________.

A. 99.55 to 99.65
B. 100.5 to 101.4
C. 97.2 to 98.5
D. 89.1 to 91.2
1Comment
SHIVAM KUMAR @shivamkumar12
8 Nov 2019 02:08 pm
overhead = 4 bytes
disk size= 100*10^6
data block size = 10^3 bytes
total page = 100*10^6/10^3 = 10^5
total overhead = 10^5*4 = 0.4*10^6 bytes
so,(100-0.4)*10^6 = 99.6*10^6
maximum size of a file that can be stored on this disk in units of 10^6 bytes = 99.6

A. 99.55 to 99.65

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