Sumit, your posts are private.
Better to make this public so that it will be visible to non-members.
30 Mar 2020 - 12:35am
Your answer is correct and it is evaluated correctly. If you notice, you have scored 2 out of 2 marks.
This is an issue at the design level and the site development team should fix this ASAP.
24 Jan 2020 - 1:35pm

24 = 16 

Note that 16 is one less than 17.
25 = 32  [ 32 + 2 is divisible ]
26 = 64  [ 64 + 4 is divisible ]
27 = 128 [ 128 + 23 is divisible]
28 = 256 [ 256 + 24  is divisible]
29  =>  29 +  2 is divisible by 17
.................................................
2n =>  2n + 2n-4

So,  2256 will be divisible by 17 iff  n + (n - 4) = 256 has integer solution

n + (n - 4) = 256
=> 2n = 260
=> n = 130

Hence, 2256 is divisible by 17

14 Jan 2020 - 2:59am
Apoorva, Please correct the question. It seems to have many typos.
23 Dec 2018 - 3:58pm
Please send me your email address with which you attended the test. I will verify and resend the code.
15 Sep 2018 - 12:19am
let me forward it again.
14 Sep 2018 - 7:44pm
The Class Room has been started and the link and the secret key has already been shared with the selected students.
14 Sep 2018 - 7:29pm
Almost Done.
Will be released by Tomorrow.
11 Sep 2018 - 10:46am

Superkeys containing AB:
AB with the combination of C, D & E = 2= 8
Superkeys containing AE:
AE with the combination of B, C & D = 2= 8

Here, we have counted the combination of ABE twice hence need to subtract them, which is:
ABE with the combination of C & D: 22 = 4

Hence the number of possible superkeys are: 8+8-4 = 12

1 Sep 2018 - 8:26pm

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